Explanation of the mass of the muon
Koschmieder, E. L.
Original · EN
The difference of the rest masses m(pi+-) - m(mu+-) is nearly equal to 1/4 of the rest mass of the pi(+-) mesons and is equal to the sum of the rest masses of the 0.7 times 10⁹ muon neutrinos (respectively anti-muon neutrinos) which are in the cubic lattice of the pi(+-) mesons according to the standing wave model. In the decay of a pi(+) or pi(-) meson all muon neutrinos, respectively anti-muon neutrinos, of the cubic lattice of the pi(+-) mesons are emitted. The sum of the oscillation energies of all neutrinos in the pi(+-) mesons is the same as the sum of the oscillation energies of the remaining neutrinos in the mu(+-) mesons. Consequently the mass of the mu(+-) mesons is equal to m(pi+-) - 0.7 times 10⁹ m(nuₘu) or 0.75 times m(pi+-), within 1% in agreement with the measured ratio m(mu+-) / m(pi+-) = 0.757028.
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