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arXiv 2013-12-26 0 views

A curious formula related to the Euler Gamma function

Farhi, Bakir

Original · EN

In this note, we prove that for all x ∈ (0, 1), we have: Γ(x) = 1/2 π+ πη (1/2 - x) - 1/2 (πx) + 1π ∑ₙ ₌ ₁∞ n/n (2 πn x), where Γ denotes the Euler Gamma function and η:= 2 ∫₀¹ Γ(x) · (2 πx) d x = 0.7687478924

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